Tóm tắt:
v1 = 8 km/h
v2 = 12km/h
\(\dfrac{1}{2}AB=s\)
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vtb = ?
Gọi nửa quãng đường là s
\(\Rightarrow v_{tb}=\dfrac{s+s}{t+t'}=\dfrac{2s}{\dfrac{s}{v_1}+\dfrac{s}{v_2}}\)
\(\Rightarrow\dfrac{2s}{s\left(\dfrac{1}{v_1}+\dfrac{1}{v_2}\right)}=\dfrac{2}{\dfrac{1}{v_1}+\dfrac{1}{v_2}}=\dfrac{2}{\dfrac{1}{8}+\dfrac{1}{12}}\)
\(=9,6\) km/h