\(3\dfrac{2}{5}=\dfrac{3\times5+2}{5}=\dfrac{17}{5}\) \(2\dfrac{4}{9}=\dfrac{2\times9+4}{9}=\dfrac{22}{9}\)
\(7\dfrac{3}{8}=\dfrac{7\times8+3}{8}=\dfrac{59}{8}\) \(15\dfrac{1}{10}=\dfrac{15\times10+1}{10}=\dfrac{151}{10}\)
Câu 2 :
\(3\dfrac{2}{5}=\dfrac{3\times5+2}{5}==\dfrac{17}{5}\)
\(2\dfrac{4}{9}=\dfrac{2\times9+4}{9}=\dfrac{22}{9}\)
\(7\dfrac{3}{8}=\dfrac{7\times8+3}{8}=\dfrac{59}{8}\)
\(15\dfrac{1}{10}=\dfrac{15\times10+1}{10}=\dfrac{151}{10}\)
\(3\dfrac{2}{5}=\dfrac{3\times5+2}{5}=\dfrac{17}{5}\)
\(2\dfrac{4}{9}=\dfrac{2\times9+4}{9}=\dfrac{22}{9}\)
\(7\dfrac{3}{8}=\dfrac{7\times8+3}{8}=\dfrac{59}{8}\)
\(15\dfrac{1}{10}=\dfrac{15\times10+1}{10}=\dfrac{151}{10}\)