Question

mk hỏi câu b bài 1 nha

 

Answer 1

\(4.\left(\frac{-1}{2}\right)^3-2.\left(\frac{-1}{2}\right)^2+3.\left(\frac{-1}{2}\right)+1\)

\(=\left(\frac{-1}{2}\right).\left[4.\left(\frac{-1}{2}\right)^2-2.\left(\frac{-1}{2}\right)+3\right]+1\)

\(=\frac{-1}{2}.\left[4.\frac{1}{4}-\left(-1\right)+3\right]+1\)

\(=\frac{-1}{2}.\left(1+1+3\right)+1\)

\(=\frac{-1}{2}.5+1\)

\(=\frac{-5}{2}+1\)

\(=\frac{-3}{2}\)