\(9,=\dfrac{\sqrt{6}\left(\sqrt{2}-\sqrt{3}\right)}{\sqrt{2}-\sqrt{3}}+\dfrac{5\left(1-\sqrt{6}\right)}{-5}-2\sqrt{6}\\ =\sqrt{6}-1+\sqrt{6}-2\sqrt{6}=-1\)
Đúng 0
Bình luận (0)