Ta có: \(n_{HgO}=\dfrac{21,7}{217}=0,1\left(mol\right)\)
PTHH: HgO + H2 -to-> Hg + H2O
Theo PTHH và đb, ta có:
\(n_{Hg}=n_{H_2}=n_{HgO}=0,1\left(mol\right)\)
a) \(=>m_{Hg}=0,1.201=20,1\left(g\right)\)
b) \(=>V_{H_2\left(đktc\right)}=0,1.22,4=2,24\left(l\right)\)