Question

K)\(\frac{7}{5}\)x-\(\frac{1}{4}\)=\(\frac{—5}{11}\)x
I)\(\frac{5}{7}\)x+\(\frac{7}{13}\)x=\(\frac{4}{3}\)

Answer 1

k) Ta có: \(\frac{7}{5}x-\frac{1}{4}=\frac{-5}{11}x\)

\(\Leftrightarrow\frac{7}{5}x-\frac{-5}{11}x=\frac{1}{4}\)

\(\Leftrightarrow\frac{102}{55}x=\frac{1}{4}\)

\(\Leftrightarrow x=\frac{1}{4}:\frac{102}{55}\)

hay \(x=\frac{55}{408}\)

Vậy: \(x=\frac{55}{408}\)

l) Ta có: \(\frac{5}{7}x+\frac{7}{13}x=\frac{4}{3}\)

\(\Leftrightarrow\frac{114}{91}x=\frac{4}{3}\)

\(\Leftrightarrow x=\frac{4}{3}:\frac{114}{91}\)

hay \(x=\frac{182}{171}\)

Vậy: \(x=\frac{182}{171}\)