\(Gọi-n_{H2}=x,n_{CO}=y\)
\(2H2+O2-->2H2O\)
x------------------------x(mol)
\(2CO+O2-->2CO2\)
y---------------------------y(mol)
\(n_{hh}=\frac{13,44}{22,4}=0,6\left(mol\right)\)
Theo bài ta có hpt
\(\left\{{}\begin{matrix}x+y=0,6\\18x+44y=21,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,2\\y=0,4\end{matrix}\right.\)
\(\%V_{H2}=\%n_{H2}=\frac{0,2}{0,6}.100\%=33,33\%\)
\(\%V_{CO}=\%n_{CO}=100-33,33=66,67\%\)