a, b là số mol X và Y
\(n_{O_2}=0,55mol;n_{CO_2}=0,35\)
\(C_nH_{2n+2}+\left(\dfrac{3n+1}{2}\right)O_2\rightarrow nCO_2+\left(n+1\right)H_2O\)
a--------------\(\dfrac{3n+1}{2}a\) ------------\(na\)
\(C_mH_{2m-2}+\left(\dfrac{3m-1}{2}\right)O_2\rightarrow mCO_2+\left(m-1\right)H_2O\)
b---------------\(\dfrac{3m-1}{2}b\)------------\(mb\)
Ta có:
\(\left\{\begin{matrix}a+b=0,25\\\dfrac{3n+1}{2}a+\dfrac{3m-1}{2}b=0,55\\na+mb=0,35\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}a+b=0,25\\a-b=0,05\\na+mb=0,35\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}a=0,15\\b=0,1\\3n+2m=7\end{matrix}\right.\)
\(\Rightarrow n=1;m=2\)\(\Rightarrow X:CH_4;Y:C_2H_2\)
