FexOy+2y HCl -------> xFeCl2y/x+ yH2O (1)
xFeCl2y/x+ 2yNaOH ---->xFe(OH)2y/x+2yNaCl (2)
2xFe(OH)2y/x+ (-4y-6x)/2 O2 -----> xFe2O3+ 2yH2O (3)
nFe2O3=0.0225 mol
Theo(3) nFe(OH)2y/x=2nFe2O3=0.045 mol
Theo(2) nFeCl2y/x=nFe(OH)2y/x=0.045 mol
Theo(1) nFexOy=1/xnFeCl2y/x=0.045/x mol
=> MFexOy=3.48/(0.045/x)=232x/3
Hay: 56x+ 16y=232x/3
=>x/y=3/4=> x=3; y=4
Vậy CTHH Fe3O4