Zn +2HCl ----->ZnCl2 +H2
a) Ta có
n\(_{H2}=\frac{0,96}{22,4}=0,043\left(mol\right)\)
Theo pthh
n\(_{Zn}=n_{H2}=0,043mol\)
m\(_{Zn}=0,043.65=2,795\left(g\right)\)
b) Theo pthh
n\(_{HCl}=2n_{H2}=0,084\left(mol\right)\)
m\(_{HCl}=0,084.36,5=3,139\left(g\right)\)
mdd =\(\frac{3,139.100}{14,6}=21,5\left(g\right)\)
C) Tự làm nhé
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