\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)
a) Pt : \(Zn+2HCl\rightarrow ZnCl_2+H_2|\)
1 2 1 1
0,1 0,2 0,1
b) \(n_{HCl}=\dfrac{0,1.2}{1}=0,2\left(mol\right)\)
\(V_{ddHCl}=\dfrac{0,2}{1}=0,2\left(l\right)\)
c) \(n_{ZnCl2}=\dfrac{0,2.1}{2}=0,1\left(mol\right)\)
\(C_{M_{ZnCl2}}=\dfrac{0,1}{0,2}=0,5\left(M\right)\)
Chúc bạn học tốt
\(a/\\ Zn+2HCl \to ZnCl_2+H_2\\ b/\\ n_{Zn}=0,1(mol)\\ n_{HCl}=0,2(mol)\\ V_{HCl}=\frac{0,2}{1}=0,2(l)\\ c/\\ n_{ZnCl_2}=0,1(mol)\\ CM_{ZnCl_2}=\frac{0,1}{0,2}=0,5M\)
