Al2O3 + 3H2SO4\(\rightarrow\)Al2(SO4)3 + 3H2O (1)
CuO + H2SO4\(\rightarrow\)CuSO4 + H2O (2)
Đặt nAl2O3=a
nCuO=b
Ta có hệ pt:
\(\left\{{}\begin{matrix}102a+80b=26,2\\3a+b=0,5\end{matrix}\right.\)
a=0,1;b=0,2
mCuO=0,2.80=16(g)
% CuO=\(\dfrac{16}{26,2}.100\%=61\%\)
%Al2O3=100-61=39%