*NTKX=(5,31.10-23):(1,6605.10-24)\(\approx\)32 đvC
Vậy X là lưu huỳnh
KHHH: S
*PTKMgCO3=NTKMg+NTKC+3NTKO=24+12+3.16=84 đvC
mMgCO3=PTKMgCO3.1,6605.10-24=84.1,6605.10-24=1,39482.10-22 g
m3MgCO3=3.mMgCO3=3.1,39482.10-22=4,18446.10-22g
*PTKCO2=NTKC+2NTKO=12+2.16=44 đvC
mCO2=PTKMgCO2.1,6605.10-24=44.1,6605.10-24=7,3062.10-23 g
m5CO2=5.mCO2=5.7,3062.10-22=3,6531.10-22g