3. a)PTHH: CaCO3\(\underrightarrow{t^o}\)CaO+CO2
b)Áp dụng định luật bảo toàn khối lượng:
mCaCO3=mCaO+mCO2
5 =2,8+mCO2
⇒mCO2=5-2,8=2,2 (tấn)
4.a)nCl2=\(\frac{mCl2}{MCl2}\)=\(\frac{0,71}{71}\)=0,01 (mol)
VCl2=22,4.nCl2=22,4.0,01=0,224 (l)
b)mCO2=nCO2.MCO2=0,5.44=22 (g)
VCO2=22,4.0,5=11,2 (l)
c)Vhh=22,4.(nO2+nN2)=22,4.(0,2+0,8)=22,4.1=22,4 (l)
mO2=nO2.MO2=0,2.32=6,4 (g)
mN2=nN2.MN2=0,8.28=22,4 (g)
mhh=mO2+mN2=6,4+22,4=28,2 (g)
d)nCO2=\(\frac{mCO2}{MCO2}\)=\(\frac{0,44}{44}\)=0,01 (mol)
nH2=\(\frac{mH2}{MH2}\)=\(\frac{0,04}{2}\)=0,02 (mol)
nN2=\(\frac{mN2}{MN2}\)=\(\frac{0,56}{28}\)=0,02 (mol)
nhh=nCO2+nH2+nN2=0,01+0,02+0,02=0,05 (mol)
Vhh=22,4.(nCO2+nH2+nN2)=22,4.0,05=1,12 (l)