mC = 12 (u) = 1,993.10-26 (kg)
rC = 1,2.10-15.A1/3 = 1,2.10-15.121/3 = 2,75.10-15 (m)
\({V_c} = \frac{4}{3}\pi {r^3} = \frac{4}{3}\pi {(2,{75.10^{ - 15}})^3} = 8,{71.10^{ - 44}}{m^3}\)
\( \to d = \frac{m}{V} = \frac{{1,{{993.10}^{ - 26}}}}{{8,{{71.10}^{ - 44}}}} = 2,{3.10^{17}}kg/{m^3}\)
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