Ta có: \(\widehat{yOt}+\widehat{xOt}=180^o\) (kề bù)
Hay: \(\widehat{yOt}+30^o=180^o\)
=> \(\widehat{yOt}=180^o-30^o=150^o\)
Mà: \(\widehat{yOt'}< \widehat{yOt}\) (vì 60o < 150o)
Nên: Tia Ot' nằm giữa hai tia Oy và Ot
=> \(\widehat{yOt'}+\widehat{t'Ot}=\widehat{yOt}\)
Hay: \(60^o+\widehat{t'Ot}=150^o\)
=> \(\widehat{t'Ot}=150^o-60^o=90^o\)