\(a.=\dfrac{x}{x-\sqrt{x}}-\dfrac{1}{x-\sqrt{x}}=\dfrac{x-1}{x-\sqrt{x}}=\dfrac{\sqrt{x}+1}{\sqrt{x}}\\ b.\sqrt{x}+1⋮\sqrt{x}=>1+\dfrac{1}{\sqrt{x}}⋮1=>\left[{}\begin{matrix}1+\dfrac{1}{\sqrt{x}}=1=>x=0\\1+\dfrac{1}{\sqrt{x}}=-1\left(loại\right)\end{matrix}\right.\)