PTHH: \(CuO+H_2\underrightarrow{t^o}Cu+H_2O\) (1)
\(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\) (2)
Đặt \(\left\{{}\begin{matrix}n_{CuO}=a\left(mol\right)\\n_{Fe_2O_3}=b\left(mol\right)\end{matrix}\right.\) \(\Rightarrow80a+160b=39,2\) (*)
Mặt khác: \(64a+2\cdot56b=29,44\) (**)
Từ (*) và (**) \(\Rightarrow\left\{{}\begin{matrix}a=0,25=n_{CuO}\\b=0,12=n_{Fe_2O_3}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{CuO}=\dfrac{0,25\cdot80}{39,2}\cdot100\%\approx51,02\%\\\%m_{Fe_2O_3}=48,98\%\end{matrix}\right.\)
Theo các PTHH: \(\Sigma n_{H_2}=n_{H_2\left(1\right)}+n_{H_2\left(2\right)}=n_{CuO}+3n_{Fe_2O_3}=0,61\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,61\cdot22,4=13,664\left(l\right)\)
