\(3^n:9=27\Rightarrow3^n:3^2=3^3\Rightarrow3^n=3^3.3^2=3^5\Rightarrow n=5\)
\(4n=64\Rightarrow n=\frac{64}{4}=16\)
\(\left(2n+1\right)^3=27\Rightarrow\left(2n+1\right)^3=3^3\Rightarrow2n+1=3\Rightarrow2n=2\Rightarrow n=1\)
\(\left(n-2\right)^2=49\Rightarrow\left(n-2\right)^2=7^2\Rightarrow n-2=7\Rightarrow n=9\)
a)3n:32=33
=>3n=33.32
=>3n=35
=>n=5
b) 4n=64
=>n=64:4=16
c)(2n+1)3=33
=>2n+1=3
=>2n=2
=>n=2
d)(n-2)2=72
=>n-2=7
=>n=9