a, Đáy lớn \(CD=DE+EC=36+10=46cm\)
\(\Rightarrow S_{ABCD}=\frac{\left(AB+CD\right).AH}{2}=\frac{\left(24+46\right).18}{2}=630\)\(cm^2\)
b, \(S_{BEC}=\frac{1}{2}.BE.EC=\frac{1}{2}.AH.EC=\frac{1}{2}.18.10=90\) \(cm^2\)
c, \(S_{ABED}=S_{ABCD}-S_{BEC}=630-90=540cm^2\)
\(\Rightarrow\frac{S_{BEC}}{S_{ABED}}=\frac{90}{540}=\frac{1}{6}\)