Ta có: \(8x-\left|4x+1\right|=x+2\)
\(\Rightarrow\left|4x+1\right|=8x-\left(x+2\right)\)
\(\Rightarrow\left|4x+1\right|=7x-2\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}4x+1=7x-2\\4x+1=2-7x\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}3x=3\\11x=1\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=1\\x=\frac{1}{11}\end{array}\right.\)