https://i.imgur.com/EMqbzIs.jpg
https://i.imgur.com/EMqbzIs.jpg
Bài 2: Phương trình bậc nhất một ẩn và cách giải
Các câu hỏi tương tự
1) Giải các pt sau:
a) frac{x-3}{5}6-frac{1-2x}{3}
b) frac{3x-2}{6}-5frac{3-2left(x+7right)}{4}
c) frac{x+8}{6}-frac{2x-5}{5}frac{x-1}{3}-x+7
d) frac{7x}{8}-5left(x-9right)frac{2x+1,5}{6}
e) frac{5left(x-1right)+2}{6}-frac{7x-1}{4}frac{2left(2x+1right)}{7}-5
f) frac{x+1}{3}+frac{3left(2x+1right)}{4}frac{2x+3left(x+1right)}{6}+frac{7+12x}{12}
Đọc tiếp
1) Giải các pt sau:
a) \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)
b) \(\frac{3x-2}{6}-5=\frac{3-2\left(x+7\right)}{4}\)
c) \(\frac{x+8}{6}-\frac{2x-5}{5}=\frac{x-1}{3}-x+7\)
d) \(\frac{7x}{8}-5\left(x-9\right)=\frac{2x+1,5}{6}\)
e) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x+1\right)}{7}-5\)
f) \(\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
Bài 1:Giải phương trình
a)10x^2-5xleft(2x+3right)15
b)3x-7-left(3-4xright)left(2x+1right)4xleft(2x-7right)
c)left(4x-5right)^2-left(7-2xright)4left(2x-4right)^2+6x
Bài 2:Giải phương trình
a)frac{3left(x-1right)}{2}+4frac{2x}{3}+frac{4-5x}{6}
b)frac{4-x}{7}-frac{1}{7}left(frac{7+3x}{9}+frac{5-2x}{2}right)4-frac{4x}{3}
c)frac{2}{9}left(2x-5right)-frac{5}{3}left[left(x-2right)-frac{7}{12}right]frac{3}{4}left(x-3right)
Bài 3:Giải phương trình
a)left(x-6right)left(2x-5right)left(3x+9right)0...
Đọc tiếp
Bài 1:Giải phương trình
a)\(10x^2-5x\left(2x+3\right)=15\)
b)\(3x-7-\left(3-4x\right)\left(2x+1\right)=4x\left(2x-7\right)\)
c)\(\left(4x-5\right)^2-\left(7-2x\right)=4\left(2x-4\right)^2+6x\)
Bài 2:Giải phương trình
a)\(\frac{3\left(x-1\right)}{2}+4=\frac{2x}{3}+\frac{4-5x}{6}\)
b)\(\frac{4-x}{7}-\frac{1}{7}\left(\frac{7+3x}{9}+\frac{5-2x}{2}\right)=4-\frac{4x}{3}\)
c)\(\frac{2}{9}\left(2x-5\right)-\frac{5}{3}\left[\left(x-2\right)-\frac{7}{12}\right]=\frac{3}{4}\left(x-3\right)\)
Bài 3:Giải phương trình
a)\(\left(x-6\right)\left(2x-5\right)\left(3x+9\right)=0\)
b)\(2x\left(x-3\right)+5\left(x-3\right)=0\)
c)\(\left(x^2-4\right)-\left(x-2\right)\left(3-2x\right)=0\)
Bài 4:Tìm m để phương trình sau có nghiệm bằng 7:\(\left(2m-5\right)x-2m^2+8=43\)
Bài 5:Giải phương trình
a)\(\left(2x-1\right)^2-\left(2x+1\right)^2=0\)
b)\(\frac{1}{27}\left(x-3\right)^3-\frac{1}{125}\left(x-5\right)^3=0\)
giải phương trình sau :
a/ x + 1 = 3x - 1
b/x - 4 +2x = 4 - x
c/\(\frac{x+3}{4}+1=\frac{1-x}{6}\)
\(\frac{2x+3}{4}=1+\frac{x-7}{5}\)
\(^{\left(x+1\right)^2-\left(x-1\right)^2=2x\left(x+1\right)-6}\)
\(\left(1+x\right)^3-\left(x-2\right)^2=9\left(x-1\right)^2\)
Giải các phương trình sau :
a) x^4-left(x^2+2right)4
b) frac{x+2}{x-2}-frac{1}{x}frac{2}{xleft(x-2right)}
c) frac{2x-10}{4}5+frac{2-3x}{6}
d) frac{2x}{left(x-3right)left(x+1right)}+frac{x}{2left(x-3right)}frac{x}{2x+2}
e) left(frac{x+2}{x}right)^2+left(frac{x}{x+2}right)^22
f) left(x-aright)left(x+aright)+2x+a^2-1
g) frac{x-a}{2a}+frac{x-2a}{3a}+frac{x-3a}{4a}+frac{x-4a}{5a}-4
h) left(x^2-3x+4right)^2left(x^2-2x+3right)left(x^2-4x+5right)
i) frac{x^2-4x+12}{x^2-4x+6}x^2-4x+8
Đọc tiếp
Giải các phương trình sau :
a) \(x^4-\left(x^2+2\right)=4\)
b) \(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)
c) \(\frac{2x-10}{4}=5+\frac{2-3x}{6}\)
d) \(\frac{2x}{\left(x-3\right)\left(x+1\right)}+\frac{x}{2\left(x-3\right)}=\frac{x}{2x+2}\)
e) \(\left(\frac{x+2}{x}\right)^2+\left(\frac{x}{x+2}\right)^2=2\)
f) \(\left(x-a\right)\left(x+a\right)+2x+a^2=-1\)
g) \(\frac{x-a}{2a}+\frac{x-2a}{3a}+\frac{x-3a}{4a}+\frac{x-4a}{5a}=-4\)
h) \(\left(x^2-3x+4\right)^2=\left(x^2-2x+3\right)\left(x^2-4x+5\right)\)
i) \(\frac{x^2-4x+12}{x^2-4x+6}=x^2-4x+8\)
Giúp mình vs mn ơi. Mai mình cần rồi :
Giải các PT:
a) 3(x-4)+5=2(x+1)-8
b) 5(x+1)2+2x=5x2-3
c) \(\frac{4\left(x+2\right)}{15}=\frac{13x-9}{40}\)
d)\(\left(\frac{3}{4}x-1\right)\left(\frac{5}{3}x+2\right)=0\)
e)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}-\frac{8}{x^2+2x-3}=1\)
Cảm ơn mn trước nhé!
bài 2
a 0,75x (x +5 )= x+5 (3- 1,25x)
b\(\frac{4}{5}x-3=\frac{1}{5}x\left(4x-15\right)\)
c(x-3) -\(\frac{\left(x-3\right)\left(2x-5\right)}{6}=\frac{\left(x-3\right)\left(3-x\right)}{4}\)
d \(\frac{\left(3x+1\right)\left(3x-2\right)}{3}+5\left(3x+1\right)=\frac{2\left(2x+1\right)\left(3x+1\right)}{3}+2x\left(3x+1\right)\)
Giải các phương trình sau:
a) frac{4}{x-1}-frac{5}{x-2}-3
b) 3x-frac{1}{x-2}frac{x-1}{2-x}
c) frac{x+4}{x^2-3x+2}+frac{x+1}{x^2-4x+3}frac{2x+5}{x^2-4x+3}
d) frac{2}{x^2-4}-frac{1}{xleft(x-2right)}+frac{x-4}{xleft(x+2right)}0
e) frac{4x}{x^2+4x+3}-16left(frac{1}{x+3}-frac{1}{2x+2}right)
f) frac{3}{4left(x-5right)}+frac{15}{50-2x^2}frac{7}{6x+30}
g) frac{1}{x-1}+frac{2x^2-5}{x^3-1}frac{4}{x^2+x+1}
Đọc tiếp
Giải các phương trình sau:
a) \(\frac{4}{x-1}-\frac{5}{x-2}=-3\)
b) \(3x-\frac{1}{x-2}=\frac{x-1}{2-x}\)
c) \(\frac{x+4}{x^2-3x+2}+\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
d) \(\frac{2}{x^2-4}-\frac{1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
e) \(\frac{4x}{x^2+4x+3}-1=6\left(\frac{1}{x+3}-\frac{1}{2x+2}\right)\)
f) \(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{7}{6x+30}\)
g) \(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
Giải các phương trình sau:
a) frac{4}{x-1}-frac{5}{x-2}-3
b) 3x-frac{1}{x-2}frac{x-1}{2-x}
c) frac{x+4}{x^2-3x+2}+frac{x+1}{x^2-4x+3}frac{2x+5}{x^2-4x+3}
d) frac{2}{x^2-4}-frac{1}{xleft(x-2right)}+frac{x-4}{xleft(x+2right)}0
e) frac{4x}{x^2+4x+3}-16left(frac{1}{x+3}-frac{1}{2x-2}right)
f) frac{3}{4xleft(x-5right)}+frac{15}{50-2x^2}frac{7}{6x+30}
g) frac{1}{x-1}+frac{2x^2-5}{x^3-1}frac{4}{x^2+x+1}
Đọc tiếp
Giải các phương trình sau:
a) \(\frac{4}{x-1}-\frac{5}{x-2}=-3\)
b) \(3x-\frac{1}{x-2}=\frac{x-1}{2-x}\)
c) \(\frac{x+4}{x^2-3x+2}+\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
d) \(\frac{2}{x^2-4}-\frac{1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
e) \(\frac{4x}{x^2+4x+3}-1=6\left(\frac{1}{x+3}-\frac{1}{2x-2}\right)\)
f) \(\frac{3}{4x\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{7}{6x+30}\)
g) \(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
Giải các phương trình:
a) \(\frac{2x}{x-1}-\frac{x}{x-2}=\frac{x^2}{\left(x-1\right)\left(x-2\right)}\)
b) \(\frac{1}{x+2}-\frac{6}{x-1}+\frac{8}{\left(x+2\right)\left(x-1\right)}=0\)
c) \(\frac{x+2}{x+3}-\frac{x+1}{x-1}=\frac{4}{\left(x+3\right)\left(x-1\right)}\)
d) \(\frac{x-1}{x+2}-\frac{x+1}{x-2}=\frac{x-3}{4-x^2}\)