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Bài 5: Phương trình chứa ẩn ở mẫu
Các câu hỏi tương tự
Giải phương trình sau:
\(\frac{4x^2-\left(x-3\right)^2}{9\left(x^2-1\right)}-\frac{x^2-9}{\left(2x+3\right)^2-x^2}+\frac{\left(2x-3\right)^2-x^2}{4x^2-\left(x+3\right)^2}=1\)
26 ,giải phương trình.
a,\(\frac{1}{x-1}+\frac{2}{x^2+x+1}=\frac{3x^2}{x^3-1}\)
b,\(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
c,\(\frac{x-1}{x+2}+\frac{x-2}{x+1}=\frac{2\left(x^2+2\right)}{x^2-4}\)
d,\(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
Giải phương trình:
a, \(\frac{2}{\left(1-3x\right)\left(3x+11\right)}=\frac{1}{9x^2-6x+1}-\frac{3}{\left(3x+11\right)^2}\)
b,\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^1-x+1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
Giải phương trình sau
a) \(\frac{3}{2\left(x+1\right)}-\frac{x-2}{9}=\frac{2x+1}{18}\)
b) \(\frac{2x}{\left(x+1\right)\left(x-2\right)}+\frac{-2}{x-1}=\frac{1}{x+2}\)
help meeeeeee!!!!!!
giải phương trình :
a) 3x(x-1)=(x-1)(x+2)
b) \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
c) \(\frac{1}{2}\left(x+1\right)+\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+2\right)\)
d) ** \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\) ưu tiên câu d nha
\(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right)\left(x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}\)
\(1.\frac{1}{x^2-2x+2}+\frac{2}{x^2-2x+3}=\frac{6}{x^2-2x+4}
\)
2.\(\frac{2x^4}{\left(x+1\right)^2}-\frac{5x^2}{x+1}+2=0\)
3.\(\left(x+\frac{1}{x}\right)^2-6\left(x+\frac{1}{x}\right)+8=0\)
4.\(\left(x^2+\frac{1}{x^2}\right)-4\left(x+\frac{1}{x}\right)+6=0\)
5.\(\frac{2x}{3x^2-x+2}-\frac{7x}{3x^2+5x+2}=1\)
Giải phương trình:
\(\left(\frac{x+1}{x-2}\right)^2+\frac{x+1}{x-4}-3\left(\frac{2x-4}{x-4}\right)^2=0\)
a) \(\frac{1}{2x-3}-\frac{3}{x\left(2x-3\right)}=\frac{5}{x}\)
b)\(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)
c)\(\frac{x +1}{x-2}+\frac{x-1}{x +2}=\frac{2\left(x^{2^{ }}+2\right)}{x^2-4}\)
d)(2x+3)\(\left(\frac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\frac{3x+8}{2-7x}+1\right)\)