Question

Giải phương trình sau:

( x - 2 ) × ( 4x + 5 ) = 0

Giúp mình nhé!!!!

Answer 1

\(\left(x-2\right)\left(4x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\4x+5=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\frac{5}{4}\end{matrix}\right.\\ \Rightarrow S=\left\{-\frac{5}{4};2\right\}\)

Answer 2

x-2=0 hoặc 4x+5=0

x=2 hoặc x=\(\frac{-5}{4}\)

Answer 3

( x - 2 ) ( 4x + 5 ) = 0

➜\(\left[{}\begin{matrix}x-2=0\\4x+5=0\end{matrix}\right.\)

➜\(\left[{}\begin{matrix}x=2\\4x=-5\end{matrix}\right.\)

➜\(\left[{}\begin{matrix}x=2\\x=\frac{-5}{4}\end{matrix}\right.\)

Vậy S∈\(\left\{2;\frac{-5}{4}\right\}\)

Answer 4

\(\left(x-2\right)\left(4x+5\right)=0\)

\(\left[{}\begin{matrix}x-2=0\\4x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=\frac{-5}{4}\end{matrix}\right.\)

Answer 5

Người gởi bài có phúc

Answer 6

(x-2)(4x+5)=0

⇔x-2=0 hoặc 4x+5=0

⇔x=2 hoặc x=-5/4

Vậy ...