\(\Leftrightarrow x^2+2x+1-\left|5-3x\right|-x=x^2+2x+4\)
\(\Leftrightarrow x+3+\left|5-3x\right|=0\)
- Với \(x\le\frac{5}{3}\)
\(\Leftrightarrow x+3+5-3x=0\)
\(\Leftrightarrow2x=8\Rightarrow x=4\left(l\right)\)
- Với \(x>\frac{5}{3}\)
\(\Leftrightarrow x+3+3x-5=0\)
\(\Leftrightarrow4x=2\Rightarrow x=\frac{1}{2}< \frac{5}{3}\left(l\right)\)
Vậy pt vô nghiệm