(1) \(4p_M+2n_M+2p_X+n_X=116\)
(2) \(2p_X+n_X=2p_M+n_M+14\)
Thế (2) vào (1) => \(4p_M+2n_M+2p_M+n_M=102\)
\(6p_M+3n_M=102\)
\(\Leftrightarrow2p_M+n_M=34\) (I)
Thế (I) vào (2) ta có: \(2p_X+n_X=48\) (II)
(I)(II) \(\Rightarrow\left\{{}\begin{matrix}2p_M+n_M=34\\2p_X+n_X=48\end{matrix}\right.\)
Éc.. hong ra kết quả :(