a) Ta có: \(3x-5+7x=17-2x+8\)
\(\Leftrightarrow10x-5=25-2x\)
\(\Leftrightarrow10x-5-25+2x=0\)
\(\Leftrightarrow12x-30=0\)
\(\Leftrightarrow12x=30\)
\(\Leftrightarrow x=\frac{30}{12}=\frac{5}{2}\)
Vậy: \(x=\frac{5}{2}\)
b) Ta có: \(13-5x+14=3x-17-9x\)
\(\Leftrightarrow27-5x=-17-6x\)
\(\Leftrightarrow27-5x+17+6x=0\)
\(\Leftrightarrow44+x=0\)
\(\Leftrightarrow x=-44\)
Vậy: x=-44
c) Ta có: \(x-12+4x=25+2x-49\)
\(\Leftrightarrow x-12+4x-25-2x+49=0\)
\(\Leftrightarrow3x+12=0\)
\(\Leftrightarrow x=-4\)
Vậy: x=-4
d) Ta có: \(7x+10+5=3\left(2x-3\right)-9x\)
\(\Leftrightarrow7x+15=6x-9-9x\)
\(\Leftrightarrow7x+15-6x+9+9x=0\)
\(\Leftrightarrow10x+24=0\)
\(\Leftrightarrow10x=-24\)
\(\Leftrightarrow x=-\frac{24}{10}=\frac{-12}{5}\)
Vậy: \(x=-\frac{12}{5}\)
