\(\frac{x}{3}\)- \(\frac{1}{2}\)= \(\frac{3x}{4}\)
\(\frac{x}{3}\)- \(\frac{2}{4}\) =\(\frac{3x}{4}\)
\(\frac{x}{3}\) = \(\frac{3x}{4}\) + \(\frac{2}{4}\)
\(\frac{x}{3}\) =\(\frac{3x+2}{4}\)
\(\Rightarrow\) 4x = 3(3x + 2)
4x=9x + 6
4x - 9x -6 = 0
-5x - 6 = 0
-5x =6
x= \(\frac{-6}{5}\)
TICK NHÉ !!!!
tìm x , y , z biết
a) \(\frac{x}{2}=\frac{y}{5}\)và 3x - y = 10
b) \(\frac{x}{4}=\frac{y}{5}\)và x.y= 30
c) \(\frac{x}{4}=\frac{y}{4};\frac{y}{3}=\frac{z}{4}\)và 4x + y.z= 16
d) \(\frac{x+1}{2}=\frac{y+2}{3}=\frac{z+2}{4}\)và 3x - 2y + z = 105
tìm x:
1) \(\frac{x-4}{12}=\frac{x-6}{11}\)
2)\(\frac{3x+2}{-7}=\frac{x-4}{-2}\)
3)\(\frac{1-4x}{5}=\frac{2x-1}{-3}\)
Tìm x
\(\frac{3^{3x}+3^{3x+2}}{3^3}=\frac{4^{2x+1}+4^{2x}}{2^3}\)
bài 1
cho tỉ lệ thức :
\(\frac{3x-y}{x+y}=\frac{3}{4}\) .tính \(\frac{x}{y}\)
bài 2:
Tìm x trong tỉ lệ thức
\(\frac{3x+2}{5x+7}=\frac{3x+1}{5x+4}\)
tìm số x , biết :
a) \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
c) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
d) \(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
e) \(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
f) \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)
Bài 1: tìm x:
a)\(\frac{2}{3}\).x-\(\frac{3}{2}\).x=\(\frac{5}{12}\)
b) \(\frac{7}{9}\):(2+\(\frac{3}{4}\).x)+\(\frac{5}{9}\)=\(\frac{23}{27}\)
c)\(\frac{2}{5}\)+\(\frac{3}{5}\).(3x-3,7)= -\(\frac{53}{10}\)
tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
Tìm x biết
a) x + \(2\frac{3}{4}=5\frac{2}{3}\)
b)X x \(3\frac{1}{2}=4\frac{3}{4}\)
c) x - \(4\frac{1}{5}=3\frac{2}{7}\)
d) x - \(\frac{3}{4}=6\text{x}\frac{3}{8}\)
e) \(\frac{7}{8}:x=3\frac{1}{2}\)
(3x-\(\frac{-1}{2}\)-\(\frac{2}{3}\)):(-10+\(\frac{1}{2}\))=\(\frac{x}{3}\)
