\(\frac{3x-11}{2}-\frac{x-3}{3}=\frac{1}{6}\)
\(\frac{3\times\left(3x-11\right)}{3\times2}-\frac{2\times\left(x-3\right)}{2\times3}=\frac{1}{6}\)
\(\frac{9x-33}{6}-\frac{2x-6}{6}=\frac{1}{6}\)
\(\frac{\left(9x-33\right)-\left(2x-6\right)}{6}=\frac{1}{6}\)
\(9x-33-2x+6=1\)
\(\left(9x-2x\right)-\left(33-6\right)=1\)
\(7x-27=1\)
\(7x=1+27\)
\(7x=28\)
\(x=\frac{28}{7}\)
\(x=4\)
Chúc bạn học tốt
\(PT\Leftrightarrow\frac{3.\left(3x-11\right)-2.\left(x-3\right)}{6}=\frac{1}{6}\)
<=> 3.(3x - 11) - 2.(x - 3) = 1
<=> 9x - 33 - 2x + 6 = 1
<=> 7x = 28
<=> x = 4
\(\frac{3x-11}{2}-\frac{x-3}{3}=\frac{1}{6}\) MC: 6
\(\Leftrightarrow\frac{3\left(3x-11\right)}{6}-\frac{2\left(x-3\right)}{6}=\frac{1}{6}\)
\(\Leftrightarrow3\left(3x-11\right)-2\left(x-3\right)=1\)
\(\Leftrightarrow9x-33-2x+6=1\)
\(\Leftrightarrow9x-2=33-6+1\)
\(\Leftrightarrow7x=28\)
\(\Leftrightarrow x=4\)
Vậy x = 4
\(\frac{3x-11}{2}\) - \(\frac{x-3}{3}\) = \(\frac{1}{6}\)
<=>\(\frac{3\left(3x-11\right)}{6}\) - \(\frac{2\left(x-3\right)}{6}\)=\(\frac{1}{6}\)
<=>\(\frac{9x-33}{6}\) - \(\frac{2x-6}{6}\) = \(\frac{1}{6}\)
=> 9x-33-2x+6=1
<=>9x-2x=33-6+1
<=>7x=28
<=>x=4
