Ta có: \(\frac{3\left(2x+1\right)}{4}-5-\frac{3x+2}{10}=\frac{2\left(3x-1\right)}{5}\)
\(\Leftrightarrow\frac{3\left(2x+1\right)}{4}-5-\frac{3x+2}{10}-\frac{2\left(3x-1\right)}{5}=0\)
\(\Leftrightarrow\frac{15\left(2x+1\right)}{20}-\frac{100}{20}-\frac{2\left(3x+2\right)}{20}-\frac{8\left(3x-1\right)}{20}=0\)
\(\Leftrightarrow30x+15-100-2\left(3x+2\right)-8\left(3x-1\right)=0\)
\(\Leftrightarrow30x+15-100-6x-4-24x+8=0\)
\(\Leftrightarrow-81=0\)(vô lý)
Vậy: \(x\in\varnothing\)