Question

\(\frac{-3}{2}\) - 2x + \(\frac{3}{4}\) = -2

Answer 1

\(\frac{-3}{2}-2x+\frac{3}{4}=-2\\ \left(\frac{-3}{2}+\frac{3}{4}\right)-2x=-2\\ \frac{-3}{4}+2-2x=0\\ \frac{5}{4}=2x\\ x=\frac{5}{8}\)

Vậy \(x=\frac{5}{8}\)

Answer 2

\(\frac{-3}{2}\)-2x+\(\frac{3}{4}\) = -2

\(\frac{-3}{2}\)-2x = -2 -\(\frac{3}{4}\)

\(\frac{-3}{2}\)-2x = \(\frac{-11}{4}\)

2x = \(\frac{-3}{2}\)-\(\frac{-11}{4}\)

2x = \(\frac{5}{4}\)

x = \(\frac{5}{4}\): 2

x = \(\frac{5}{8}\)

Answer 3

$\frac{-3}{2}$ - 2x + $\frac{3}{4}$ = -2

⇔\(\frac{-3}{2}-2x=-2-\frac{3}{4}\)

⇔\(\frac{-3}{2}-2x=\frac{-11}{4}\)

⇔\(2x=\frac{-3}{2}-\frac{-11}{4}\)

⇔\(2x=\frac{-3}{2}+\frac{11}{4}\)

⇔\(2x=\frac{5}{4}\)

⇔\(x=\frac{5}{4}\div2\)

⇔\(x=\frac{5}{8}\)