2Ca + O2 \(\rightarrow\)2CaO (1)
2Zn + O2 \(\rightarrow\)2ZnO (2)
nO2=\(\dfrac{8}{32}=0,25\left(mol\right)\)
Đặt nCa=a
nZn=b
Ta có:
\(\left\{{}\begin{matrix}40a+65b=27,5\\0,5.\left(a+b\right)=0,25\end{matrix}\right.\)
=>a=0,2;b=0,3
mCa=40.0,2=8(g)
%mCa=\(\dfrac{8}{27,5}.100\%=29,1\%\)
%mZn=100-29,1=70,9%
b;
mchất rắn=mKL +mO=27,5+8=35,5(g)