a)\(2Cu+O2-->2CuO\)
b)\(n_{Cu}=\frac{16}{64}=0,25\left(mol\right)\)
\(n_{O2}=\frac{1}{2}n_{Cu}=0,125\left(mol\right)\)
\(V_{O2}=0,125.22,4=2,8\left(l\right)\)
c)\(CuO+H2-->Cu+H2O\)
\(n_{CuO}=n_{Cu}=0,25\left(mol\right)\)
\(n_{Cu}=n_{CuO}=0,25\left(mol\right)\)
\(m_{Cu}=0,25.64=16\left(g\right)\)