a) \(PTHH:4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
b) \(n_{Al}=\frac{m_{Al}}{M_{Al}}=\frac{5,4}{27}=0,2\left(mol\right)\)
Theo PTHH, ta có:
\(n_{Al_2O_3}=\frac{2}{4}n_{Al}=\frac{1}{2}n_{Al}=\frac{1}{2}.0,2=0,1\left(mol\right)\)
\(m_{Al_2O_3}=n_{Al_2O_3}.M_{Al_2O_3}=0,1.102=10,2\left(g\right)\)
b) Theo PTHH, ta có:
\(n_{O_2}=\frac{3}{4}n_{Al}=\frac{3}{4}.0,2=0,15\left(mol\right)\)
\(V_{O_2}=n_{O_2}.22,4=0,15.22,4=3,36\left(l\right)\)
\(V_{kk}=5V_{O_2}=5.3,36=16,8\left(l\right)\)