a) \(n_{H_2}=\dfrac{2,8}{22,4}=0,125\left(mol\right)\)
PTHH: \(2H_2+O_2\underrightarrow{t^0}2H_2O\)
Theo PTHH: \(n_{H_2}:n_{O_2}=2:1\)
\(\Rightarrow n_{O_2}=n_{H_2}.\dfrac{1}{2}=0,125.\dfrac{1}{2}=0,0625\left(mol\right)\)
\(\Rightarrow V_{O_2\left(đktc\right)}=0,0625.22,4=1,4\left(l\right)\)
\(\Rightarrow m_{O_2}=0,0625.32=2\left(g\right)\)
b) Theo PTHH: \(n_{H_2}:n_{H_2O}=2:2=1\)
\(\Rightarrow n_{H_2O}=n_{H_2}=0,125\left(mol\right)\)
\(\Rightarrow m_{H_2O}=0,125.18=2,25\left(g\right)\)
PTHH: \(2H_2+O_2\underrightarrow{t^o}2H_2O\\ 0,125mol:0,0625mol\rightarrow0,125mol\)
\(n_{H_2}=\dfrac{2,8}{22,4}=0,125\left(mol\right)\)
a. \(V_{O_2}=0,0625.22,4=1,4\left(l\right)\)
\(m_{O_2}=0,0625.32=2\left(g\right)\)
b. \(m_{H_2O}=0,125.18=2,25\left(g\right)\)