PTHH: \(S+O_2\xrightarrow[]{t^o}SO_2\)
a) Ta có: \(n_{O_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)=n_{S\left(p/ứ\right)}\)
\(\Rightarrow m_{S\left(p/ứ\right)}=0,1\cdot32=3,2\left(g\right)\) \(\Rightarrow m_{tạp.chất}=3,25-3,2=0,05\left(g\right)\)
b) Ta có: \(\%m_S=\dfrac{3,2}{3,25}\cdot100\%\approx98,46\%\)