20oC ứng với:
\(20\cdot1,8+32=68\left(^oF\right)\)
256oC ứng với:
\(256\cdot1,8+32=492,8\left(^oF\right)\)
Ta có :
+) 20\(^o\)C= ?\(^o\)F
=>20\(^o\)C=0\(^o\)C+20\(^o\)C
= 32\(^o\)F+( 20.1,8\(^o\)F ) = 68\(^o\)F
+) 256\(^o\)C=?\(^o\)F
=>256\(^o\)C=0\(^o\)C+256\(^o\)C
= 32\(^o\)F+( 256\(^o\)C.1,8\(^o\)F ) = 492,8\(^o\)F
\(^o\)\(^o\)