Question

\(\dfrac{x}{a}+\dfrac{y}{b}+\dfrac{z}{c}=0\) và \(\dfrac{a}{x}+\dfrac{b}{y}+\dfrac{c}{z}=2\)

Tnh A=\(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}\)

Answer 1

đề bài sai k ạ