\(\dfrac{2x-9}{240}=\dfrac{117}{240}\)
=> 2x -9=117
2x=117+9
2x=126
x=126/2
x=63
\(\dfrac{2x-9}{240}\)=\(\dfrac{117}{240}\)
►2x-9=117
2x=117+9
2x=126
x=126:2
x=63
Vậy:x=63
\(\dfrac{2x-9}{240}=\dfrac{39}{80}=\dfrac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(2x=117-9\)
\(2x=108\)
\(x=108:2\)
\(x=54\)
Vậy: \(x=54\)
\(\dfrac{2x-9}{240}=\dfrac{39}{80}=\dfrac{117}{240}\)
\(\Rightarrow2x-9=117\)
\(2x=117+9\)
\(2x=126\)
\(x=126:2\)
\(x=63\)
Vậy: \(x=63\)