Solution
Let 10 ray be AA1, AA2, AA3, ..., AA10.
AA1 and AA2 or AA3 . . . . . or AA10 have 9 angles .
AA2 and AA3 or AA4 or . . . . or AA10 have 8 angles.
Then AA9 and AA10 have 1 angle .
Thus 10 rays have common vertex , have :
1 + 2 + 3 + . . . . + 9 .
= ( 9 + 1 ) * 9 : 2
= 10 * 9 : 2
= 90 : 2
= 45 .
Thus , there are 45 angles .