PTHH
CO2 Ca(OH)2 --> CaCO3
nCaCO3 =0.1 mol
=>nCO2 = nCaCO3 = 0.1 mol
=> VCO2 = 2.24 l
PTHH : CO2+Ca(OH)2--->CaCO3
=>nCaCO3= 0,1 mol
Mà nCaCO3= nCO2
=> nCO2= 0,1 (mol)
=>V= 0,1.22,4= 2,24l
CO2 + Ca(OH)2---->CaCO3 +H2O
n\(_{CaCO3}=\frac{10}{100}=0,1\left(mol\right)\)
Theo pthh
n\(_{CO2}=n_{CaCO3}=0,1\left(mol\right)\)
V\(_{CO2}=0,1.22,4=2,24\left(l\right)\)
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