a)\(CuO+CO-->Cu+CO2\)
\(n_{Cu}=\frac{8}{80}=0,1\left(mol\right)\)
\(n_{Cu}=n_{CuO}=0,1\left(Mol\right)\)
=>\(m_{Cu}=0,1.64=6,4\left(g\right)\)
\(H\%=\frac{6,4}{6,56}.100\%=97,56\%\)
b) \(Cu+2H2SO4-->CuSO4+2H2O+SO2\)
\(n_{SO2}=n_{Cu}=0,1\left(mol\right)\)
\(V_{SO2}=0,1.22,4=2,24\left(l\right)\)