nhh khí = 2,24/22,4 = 0,1 (mol)
nBr2 = 8/160 = 0,05 (mol)
PTHH: C2H2 + 2Br2 -> C2H2Br4
Mol: 0,025 <--- 0,05
%VC2H2 = 0,025/0,1 = 25%
%VCH4 = 100% - 25% = 75%
C2H2+2Br2->C2H2Br4
0,025----0,05
n Br2=\(\dfrac{8}{160}=0,05mol\)
=>%VC2H2=\(\dfrac{0,05.22,4}{2,24}.100=50\%\)
=>%CH4=50%