Question

Chứng tỏ rằng: 1/2^2+1/3^2+1/4^2+.....+1/100^2<3/4

Answer 1

Ta có:

Xét số a. Ta có a² > (a - 1)(a + 1)

Thật vậy, (a - 1)(a + 1) = a(a + 1) - (a + 1) = a² + a - a - 1 = a² - 1 < a²

Suy ra \(\dfrac{1}{\left(a-1\right)\left(a+1\right)}>\dfrac{1}{a^2}\)

Ta có:

\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{100^2}\)

\(< \dfrac{1}{1.3}+\dfrac{1}{2.4}+\dfrac{1}{3.5}+...+\dfrac{1}{99.101}\)

\(=\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\)

\(=\dfrac{1}{2}\left(1+\dfrac{1}{2}-\dfrac{1}{100}-\dfrac{1}{101}\right)\)

\(< \dfrac{3}{4}\)

Ko bt có sai chỗ nào ko....