a, pt Zn + 2HCl → Zn Cl2 + H2 (1)
CuO + H2 → Cu + H2O (2)
b, nCuO = \(\frac{8}{80}\)= 0,1 mol
theo pt (2) ta có : nCuO = n\(H_2\) = nCu = 0,1mol
theo pt (1) ta có : n\(H_2\)= nZn = \(\frac{1}{2}\)nHCl →nZn = 0,1mol , nHCl = 0,2mol
mHCl = nHCl . MHCl = 0,2 . 36,5 = 7,3 g
mZn = nZn . MZn = 0,1 . 65 = 6,5g
c, m CuO = n CuO . MCuO = 0,1 . 64 = 6,4 g
FOLLOW IK !!!!!!