Cauchy-Schwarz và AM-GM:
\(P^2=\left(13\sqrt{x^2-x^4}+9\sqrt{x^2+x^4}\right)^2\)
\(\le\left(13+27\right)\left(13\left(x^2-x^4\right)+3\left(x^2+x^4\right)\right)\)
\(=40x^2\left(16-10x^2\right)\)
\(\le4\cdot\dfrac{\left(10x^2+16-10x^2\right)^2}{4}=256\)
\(\Rightarrow P^2\le256\Rightarrow P\le16\)
Dấu "=" bạn tự tìm nhé