\(n_{CO_2}=\dfrac{13.44}{22.4}=0.6\left(mol\right)\)
\(n_Y=n_{ankan}=\dfrac{6.72}{22.4}=0.3\left(mol\right)\)
\(\text{Số nguyên tử C trong ankan : }\) \(\dfrac{0.6}{0.3}=2\)
\(CT:C_2H_6\)
\(n_{anken}=\dfrac{10.08-6.72}{22.4}=0.15\left(mol\right)\)
\(M_{anken}=\dfrac{6.3}{0.15}=42\left(\dfrac{g}{mol}\right)\)
\(\Leftrightarrow14n=42\)
\(\Leftrightarrow n=3\)
\(CT:C_3H_6\)