a, \(I_R=I_{A1}-I_{A2}=1-0,4=0,6\left(A\right)\)
ta có \(U_{DE}=\left(R_a+2R\right).0,4\)
\(U_R=0,6.R\)
\(U_{DE}=U_R\) \(\Leftrightarrow0,6R=\left(R_a+2R\right)0,4\Leftrightarrow\dfrac{R}{R_a}=-2\)
b,\(U_{CE}=U_{CD}+U_{DE}=1.\dfrac{-R}{2}+0,6R=0,1R\)
\(I_A=I_{A_1}+I_R=...\)