a: \(P=\dfrac{x-2\sqrt{x}+6\sqrt{x}+4}{x-4}:\dfrac{2\sqrt{x}-4-\sqrt{x}+7}{\sqrt{x}-2}\)
\(=\dfrac{\left(\sqrt{x}+2\right)^2}{x-4}\cdot\dfrac{\sqrt{x}-2}{\sqrt{x}+3}=\dfrac{\sqrt{x}+2}{\sqrt{x}+3}\)
b: Khi x=16 thì \(P=\dfrac{4+2}{4+3}=\dfrac{6}{7}\)
c: Vì 2<3 nên P<1