\(n_{HCl}=0,25.0,2=0,05\left(mol\right)\)
PTHH: \(Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
a) Theo PT: \(\Rightarrow m_{Fe}=\frac{0,05}{2}.56=1,4\left(g\right)\)
b) Theo PT: \(\Rightarrow V_{H_2}=\frac{0,05}{2}.22,4=0,56\left(l\right)\)
c)Theo PT: \(n_{FeCl_2}=\frac{1}{2}n_{H_2}=0,025\left(mol\right)\)
\(\Rightarrow C_{M-FeCl_2}=\frac{0,025}{0,25}=0,1M\)